((n/2)^2)-3n

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Solution for ((n/2)^2)-3n equation: 


n in (-oo:+oo)

(n/2)^2-(3*n) = 0

(n/2)^2-3*n = 0

1/4*n^2-3*n = 0

DELTA = (-3)^2-(0*1/4*4)

DELTA = 9

DELTA > 0

n = (9^(1/2)+3)/(1/4*2) or n = (3-9^(1/2))/(1/4*2)

n = 12 or n = 0

n in { 0, 12 }

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